Hi, I wanted to know if the radius of the subhalos are taken into account when I calculate the distance between two subhalos. I made a function to calculate the distance between the central subhalo of a halo and some satellite given. Let's say I find a distance of about 20 kpc, how do I know if this is within the radius of the central or satellite halo? I used the 'SubhaloHalfmassRad' field to get an approximate radius for the central and it gives around ~ 186kpc. So in this case, would the satellite be "contained" in the central? I might be misunderstanding how these radii are defined perhaps...
Dylan Nelson
17 Nov
If you are considering two satellite subhalos, then everything you say makes sense and is rather well posed.
However, the situation for the central subhalo is somewhat different: you should really think of a "central subhalo" as, in fact, the halo. So the radius/size of a central is essentially the size of the halo, and then by definition, many (although not all) satellites will be within this radius.
Hi, I wanted to know if the radius of the subhalos are taken into account when I calculate the distance between two subhalos. I made a function to calculate the distance between the central subhalo of a halo and some satellite given. Let's say I find a distance of about 20 kpc, how do I know if this is within the radius of the central or satellite halo? I used the 'SubhaloHalfmassRad' field to get an approximate radius for the central and it gives around ~ 186kpc. So in this case, would the satellite be "contained" in the central? I might be misunderstanding how these radii are defined perhaps...
If you are considering two satellite subhalos, then everything you say makes sense and is rather well posed.
However, the situation for the central subhalo is somewhat different: you should really think of a "central subhalo" as, in fact, the halo. So the radius/size of a central is essentially the size of the halo, and then by definition, many (although not all) satellites will be within this radius.
This really helps, thank you!